My good friend and SuperMathGuru, Christopher Duff, addresses the issue as follows:
I would say yes provided the answer to the 2nd question is yes. Suppose you fix the big circle and the chord AB as it is. Then […]

Good job, Jver!!! Your award will be sent to you via PayPal later today!
Your lucidity and level of detail is astonishing! The resolution of the other problems posted by help-needing members is also […]

x^2+x-12≥ 0
For starters, this is the same as
(x+4)(x-3)≥ 0
The graph intersects the y axis at x=-4 and x=3.
This is a parabola in a “vertical position opening in the upward direction”. Sorry I can’t graph it […]

Which is (1±3√2)/5
Thanks TheMathProf! Thanks a lot! If you don’t mind, please copy and paste this excellent answer to the same problem on our Facebook page, posted by the same member! And thanks for being a […]

I am not sure that the problem is stated properly. Square root property is used when solving quadratic equations. There is no 2nd degree term here.

I am sorry. I had to correct my answer. My apologies. The Facebook answer was the correct answer.

a+b=35,000, where a is invested at 2.5% and b is invested at 3.5%
Total interest is .025a+.035b=1,075
We have 2 equations:
a+b=35,000
.025a+.035b=1,075
Multiply the first one by .025 and subtract from the 2nd one […]

Hello, Member! Please post your problem on the appropriate Forum above for immediate action by other members! Thanks!
Alex, ÜberMathGuru

No problem at all, Parth! Your help is immensely welcome ALL THE TIME! Just clarifying things. If this was addressed in another Forum, then we’re ok!

Parth, your answer, “i just told you the answer ?? it is
-x^2+8x+10″, was not correct.

Sorry! Didn’t see your comment on the Blog:
2x+3y=21
Subtract 2x from both sides:
3y=21-2x;
Divide both sides by 3:
y=(21-2x)/3
Then y=7-2x/3

2x+3y=21
y=7-(2x/3)
Get x from the first equation;
2x=21-3y;
x=(21-3y)/2
Then plug that in the 2nd equation:
y=7-{[2(21-3y)/2]/3};
y=7-(21-3y)/3;
y=7-7+y;
NO PROGRESS here
Apparently, you’re missing a 2nd equation […]

7 apples.
- signed A Real Person, indeed

Once again, Thanks so much for your ongoing help! We need to help those who need it!

Juan! Thanks so much for your ongoing help! We need to help those who need it!
Alex R. Argimón, ÜberMathGuru

Parth! Thanks so much for your ongoing help! We need to help those who need it!
Alex R. Argimón, ÜberMathGuru