This topic contains 5 replies, has 4 voices, and was last updated by 2plus2 3 years, 2 months ago.
You must be logged in to reply to this topic.
Tagged: calculus, derivative, nth
This topic contains 5 replies, has 4 voices, and was last updated by 2plus2 3 years, 2 months ago.
Author  Posts 

Author  Posts 
February 23, 2012 at 5:14 pm #432  
pin690 Member

What is the nth derivative of nx^n? 
February 23, 2012 at 8:06 pm #438  
thecalculuskid Member

The first derivative is (n)(n)x^(n1)=(n^2)x^(n1). The second derivative is (n^2)(n1)x^(n2). The third derivative is (n^2)(n1)(n2)x^(n3). Interestingly, the nth derivative would be (n^2)(n1)(n2)(n3)….[n(n2)][n(n1)]x^(nn) where x^(nn) is x^0, which is equal to 1, so that term kind of “diappears”…. The other factors can be looked upon in the reverse order and you would get: (1)(2)(3)….(n3)(n2)(n1)n^2 n^2 can be broken down into (n)(n). Hence the nth derivative is n! times n or ….. nn! 
February 23, 2012 at 8:12 pm #442  
practicaldave Member

Good answer @thecalculuskid 
February 23, 2012 at 8:14 pm #443  
thecalculuskid Member

Thanks practicaldave. 
February 23, 2012 at 8:15 pm #444  
thecalculuskid Member

So, what do you think pin? Do I get the point? 
February 23, 2012 at 8:17 pm #445  
2plus2 Member

Yes, great answer. 
You must be logged in to reply to this topic.
Comments are closed, but trackbacks and pingbacks are open.
Copyright © 2011  All Rights Reserved  YourMathGuru®  Powered By MateMedia  Your Partner on The Web®